a) 20 days

b) 18 days

c) 16 days

d) 15 days

Correct Answer: D

Let one day work of skilled semi-skilled and unskilled worker be a, b, c units respectively.

5a×20= 8b×25=10c×30= Total unit of work

100a= 200b = 300c

a= 2b= 3c

b= a/2 and c= a/3

given that 2 skilled, 6 semi skilled and 5 unskilled workers are working. Let they finish the work in 'x' days.

( 2a+3b+5a/3) x = 5a × 20

20ax/3= 5a×20

X= 15 days

2) A car travels 8 km in the first quarter of an hour, 6 km in the second quarter and 16km in the third quarter. The average speed of the car in km per hour over the entire journey is?

a) 30

b) 36

c) 40

d) 24

Correct Answer: C

Average speed= Total distance/ total time

Total distance/ total time = (8+6+16) km/ (1/4 + 1/4 + 1/4 ) hrs.

= 40km/ hr

3) Raju has 14 currency notes in his pocket consisting of only Rs. 20 notes and Rs. 10 notes. The total money value of the note is Rs. 230. The number of Rs. 10 notes that Raju has is?

a) 5

b) 6

c) 9

d) 10

Correct Answer:ALet the number of Rs. 20 notes be 'a' and Rs. 10 notes be 'b' respectively.So, a+b= 1420a+ 10b= 230On solving a= 9 ,b= 5Hence the number of Rs. 10 notes are 5

4. What is the change that a leap year, selected at random, will contain 53 Saturdays?

a) 2/7

b) 3/7

c) 1/7

d) 5/7

Correct Answer:A

Every leap year will have 366 days

1 leap year = 366 days

= 52× 7+2 days

Every leap year will have 52 complete weeks. For 53rdSaturday there are two favorable cases from 7 possible cases

Friday Saturday

Saturday Sunday

Sunday Monday

Monday Tuesday

Tuesday Wednesday

Wednesday Thursday

Thursday Friday

2 favorable casesRequired probability = 2/7

**5. What is the next number in the series**

12 35 81 173 357 _

a) 725

b) 752

c) 750

d) 758

6. Find the odd one from the following group:Correct Answer:A

difference between consecutive terms of the series are23,46,92,184, _That is multiple of 23 with 1,2,4,8 respectivelySo the next term will be 357+(23*16)= 725

WEKO IQWA FNTX NVBD

a) WEKO

b) IQWA

c) FNTX

d) NVBD

7. A train that is 280 meters long, traveling at a uniform speed, crosses a platform in 60 seconds and passes a man standing on the platform in 20 seconds. What is the length of the platform in meters?Correct Answer:DDifference between 1^{st}and 4^{th}, 2^{nd}and 3^{rd}letters in each series respectively is same expect NVBD

a) 560m

b) 506m

c) 566m

d) 562m

8. Fill in the missing number in the series.Correct Answer:Alet the length of the platform is x and velocity of train is vdistance = velocity × time(280+ x) = v × 60 (1)280 = v× 20 (2)From 1 and 2 we getX= 560m

2 3 6 15 _ 157.5 630

a) 49

b) 46

c) 43

d) 45

9. Find the odd one in the following groupCorrect Answer:D2 , 3 , 6 , 15 , _ , 157.5 , 6302× 1.5 = 33× 2 = 66× 2.5= 1515× 3 =4545×3.5=157.545 is the missing term of the series

QWZB BHKM WCGJ MSVX

a) QWZB

b) BHKM

c) WCGJ

d) MSVX

10. The next term in the series 81 54 36 24 _ is ?Correct Answer:Cadding 6,3, and 2 gives the consecutive letters.Only c doesn’t follow

a) 4

b) 8

c) 16

d) 12

Correct Answer:C

alternate terms are perfect squares 9^2, 6^2, 4^2 and in between terms are products 9×66×4 and so on missing term is4^2= 16

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